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rakiru
888b3e871a
Since this means there's multiple possible answers, I made it so that the answer can now be a function, and that gets run with the guess. This may open the door to other puzzle ideas that have been ignored due to having more than one correct answer.
47 lines
1.7 KiB
Python
47 lines
1.7 KiB
Python
#!/usr/bin/python
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import random
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import inflect
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p = inflect.engine()
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dictionary = "/usr/share/dict/american-english-small"
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BAD_WORDS_FILE = "badwords.txt"
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def get_wordlist():
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# I feel weird calling this "get_wordlist" when it's a generator without calling out that I do in fact realise it's weird - ~deltawitch
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with open(BAD_WORDS_FILE, "r") as fp:
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bad_words = set(fp)
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for word in open(dictionary).readlines():
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if "'" not in word and word not in bad_words:
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yield word.rstrip()
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def get_puzzle():
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dict_words = list(get_wordlist())
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words = random.sample(dict_words, 3)
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key = random.randrange(0,3) #get values 1-3
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puzzle = "When alphebetized, what is the " + p.ordinal(p.number_to_words(key+1)) + " in " + ", ".join(words)
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words.sort()
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answer = words[key]
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return [answer, puzzle]
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def get_anagram(maxlen = 6):
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dict_words = [word for word in get_wordlist() if len(word) > 2 and len(word) <= maxlen+1]
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word = random.choice(dict_words)
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while True:
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anagram = ''.join(random.sample(word, len(word)))
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if anagram != word:
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break
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puzzle = "Unscramble the following word: '" + anagram + "'"
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# Anagrams can have multiple answers, so we provide a check function that accepts all possibilities
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def answer_checker(guess):
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# Check for exact match
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if guess == word:
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return True
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# Bail out early if they didn't even use all the same letters
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if sorted(guess) != sorted(word):
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return False
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# Ok, gotta actually check if it's a word now
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return any(guess == item for item in get_wordlist())
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return [answer_checker, puzzle]
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