Optimize Day 2 solution: 41x faster Part 1, 18x faster Part 2

- Changed from brute-force iteration to generating invalid numbers directly
- Part 1: 45.0ms → 1.1ms
- Part 2: 69.6ms → 3.8ms
- Total benchmark time: 119.38ms → 9.68ms
This commit is contained in:
Russell Champoux committed 2025-12-05 11:49:44 -05:00
1 parent 702221e78f
commit 491f89f523
2 files changed
+68 -32

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@@ -1,4 +1,5 @@
use itertools::Itertools;
use std::collections::HashSet;
advent_of_code::solution!(2);
@@ -11,49 +12,84 @@ fn parse_range(s: &str) -> Option<(u64, u64)> {
.and_then(|(a, b)| Some((a?, b?)))
}
/// Check if a number is "invalid" - made of a pattern repeated exactly twice
fn is_invalid_part1(n: u64) -> bool {
let s = n.to_string();
let len = s.len();
// Must have even length for pattern to repeat exactly twice
len % 2 == 0 && s[..len / 2] == s[len / 2..]
/// Generate all invalid numbers (pattern repeated exactly twice) within [min, max]
fn generate_invalid_part1(min: u64, max: u64) -> Vec<u64> {
let mut result = Vec::new();
let max_digits = max.ilog10() as usize + 1;
// Pattern length k produces numbers with 2k digits
for pattern_len in 1..=max_digits / 2 {
let pattern_min = if pattern_len == 1 { 1 } else { 10u64.pow(pattern_len as u32 - 1) };
let pattern_max = 10u64.pow(pattern_len as u32) - 1;
for pattern in pattern_min..=pattern_max {
// Construct number by repeating pattern twice
let num = pattern * 10u64.pow(pattern_len as u32) + pattern;
if num >= min && num <= max {
result.push(num);
}
}
}
result
}
/// Check if a number is "invalid" - made of a pattern repeated at least twice
fn is_invalid_part2(n: u64) -> bool {
let s = n.to_string();
let len = s.len();
/// Generate all invalid numbers (pattern repeated at least twice) within [min, max]
fn generate_invalid_part2(min: u64, max: u64) -> Vec<u64> {
let mut seen = HashSet::new();
let max_digits = max.ilog10() as usize + 1;
// Try each possible pattern length (1 to len/2)
(1..=len / 2).any(|pattern_len| {
// Pattern can only work if it divides evenly
len % pattern_len == 0 && {
let pattern = &s[..pattern_len];
// Check if all chunks match the pattern
s.as_bytes()
.chunks(pattern_len)
.all(|chunk| chunk == pattern.as_bytes())
// For each pattern length
for pattern_len in 1..=max_digits / 2 {
let pattern_min = if pattern_len == 1 { 1 } else { 10u64.pow(pattern_len as u32 - 1) };
let pattern_max = 10u64.pow(pattern_len as u32) - 1;
let multiplier = 10u64.pow(pattern_len as u32);
// For each number of repetitions (at least 2)
for reps in 2..=max_digits / pattern_len {
for pattern in pattern_min..=pattern_max {
// Build number by repeating pattern
let mut num = 0u64;
for _ in 0..reps {
num = num * multiplier + pattern;
}
if num >= min && num <= max {
seen.insert(num);
}
}
}
})
}
seen.into_iter().collect()
}
pub fn part_one(input: &str) -> Option<u64> {
let sum = input
.split(',')
.filter_map(|part| parse_range(part))
.flat_map(|(start, end)| start..=end)
.filter(|&n| is_invalid_part1(n))
let ranges: Vec<(u64, u64)> = input.split(',').filter_map(parse_range).collect();
let global_min = ranges.iter().map(|r| r.0).min().unwrap_or(0);
let global_max = ranges.iter().map(|r| r.1).max().unwrap_or(0);
let invalid_nums = generate_invalid_part1(global_min, global_max);
let sum = invalid_nums
.iter()
.filter(|&&n| ranges.iter().any(|&(start, end)| n >= start && n <= end))
.sum();
Some(sum)
}
pub fn part_two(input: &str) -> Option<u64> {
let sum = input
.split(',')
.filter_map(|part| parse_range(part))
.flat_map(|(start, end)| start..=end)
.filter(|&n| is_invalid_part2(n))
let ranges: Vec<(u64, u64)> = input.split(',').filter_map(parse_range).collect();
let global_min = ranges.iter().map(|r| r.0).min().unwrap_or(0);
let global_max = ranges.iter().map(|r| r.1).max().unwrap_or(0);
let invalid_nums = generate_invalid_part2(global_min, global_max);
let sum = invalid_nums
.iter()
.filter(|&&n| ranges.iter().any(|&(start, end)| n >= start && n <= end))
.sum();
Some(sum)